vemoestacion.be About MyBB MyBB.com is the easiest way to install and manage the popular MyBB Forum Module. With just a few clicks you can install, activate and fully customize your forum. We provide for you free of charge a clean install of MyBB and the very popular MyBB Caddy Module. Text-only version Text-only version Support Questions, Problems or Need Help? The support is a community based system here to help you quickly.Q: Alternative methods of solving equations with logarithms? I’m not so much looking for just the answer, but an explanation as to why things work the way they do. I was teaching my 9th grade mathematics class on logarithms and got to the following exercise: Problem: Solve $2^n = 3\log_2 n$ and $(2^n)^{\log_2 n} = 9$ This of course, was a rather impossible-seeming equation. I gave the pupils a problem and told them to “get rid of the logs”, for example, they should use $(\log_2 3)^{2^n}$. Questions: Why does this work? Why does this work? Can you in general solve other equations like this without using logarithms? Of course, I also find it intriguing to use this method and show that $n$ and $\log_2 3$ are related in some way. A: Hint $$2^n = \sqrt[\log_2]9 = \log_2\sqrt[\log_2]{9}= \log_2\sqrt[\log_2]{3\log_2 n}$$ # Please don’t modify this file. # To contribute on translations, go to report.minimize.title=ပြည့်စုံကိရေးမှမလုပ်နိုင်�